In ABC, B = 90º, AC = 12 cm, BC = 6 cm. Find measure of A
Answers
Answer:
Angle A= 45º
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Question :-
In ∆ABC, ∠B = 90º, AC = 12 cm, BC = 6 cm. Find measure of ∠A.
Given :-
A ∆ABC in which ,
∠B = 90°
AC = 12 cm
BC = 6 cm
To Find :-
Measure of ∠A
Solution :-
We will use trigonometric identities to solve this question.
We know that,
Sin A = Perpendicular/Hypotenuse.
Sin A = P/H
Refer to the figure to check the values.
According to the figure, we have values of perpendicular and hypotenuse with respect to angle A.
Perpendicular = BC = 6 cm
Hypotenuse = AC = 12 cm
Put these values in the Sine formula,
Sin A = BC/AC
= 6/12
= 1/2
Sin A = 1/2
We know that at θ = 30°, the value of sine function is 1/2,
So, measure of ∠A is 30°.
Final Answer :-
∠A = 30°
Some extra information :-
Sin A = P/H
Cos A = B/H
Tan A = P/B
Cosec A = H/P
Sec A = H/B
Cot A = B/P
Where,
P = Perpendicular
H = Hypotenuse
B = Base