Question

In ∆ ABC, ∠B = 90o, then sin (A + C) is.​

Answer 1

Given : in triangle abc, angle c=90°

To Find :  sin(a+b) ​

Solution:

In any triangle sum of all angles of triangle is 180°

Hence ∠a + ∠b + ∠c  = 180°

∠c = 90°   given

=> ∠a + ∠b + 90° = 180°

=> ∠a + ∠b = 90°

sin(a+b) ​   = Sin (90°)  

=> sin(a+b) ​  = 1

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Answer 2

Answer:

root 2 by 4

Step-by-step explanation:

because 1 angle is 90 degree so we know total perimeter of triangle will be 180 degree so

2x=180-90

x=45 so a and c each 45 degree now value of sin 45 is 1 by root 2