in ΔABC, B-D-C and BD =7,BC=20 then find following ratios
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Step-by-step explanation:
Draw AE ⊥ BC, B – E – C. BC = BD + DC [B – D – C]
∴ 20 = 7 + DC
∴ DC = 20 – 7 = 13
i. ∆ABD and ∆ADC have same height AE.
A(ΔABD)/A(ΔADC) = BD/DC [Triangles having equal height]
∴ A(ΔABD)/A(ΔADC) = 7/13
ii. ∆ABD and ∆ABC have same height AE.
A(∆ABD)/A(∆ABC) = 7/20 [Triangles having equal height]
∴ A(ΔABD)/A(ΔABC) = 7/20
iii. ∆ADC and ∆ABC have same height AE.
A(ΔADC)/A(ΔABC) = DC/BC [Triangles having equal height]
∴ A(ΔADC)/A(ΔABC) = 13/20
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