in ∆ABC,b-d-c and bd=8,bc=20,find the following ratio:
1)A(∆ABD)
_______
A(∆ADC)
2)A(∆ABD)
_______
A(∆ABC)
3)A(∆ADC)
_______
A(∆ABC)
please solve I will mark brilianist
amanvyas1092442:
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According to the question, there is a triangle ABC with a point D on BC such that it divides the side BC in the ratio 8:(20-8) = 8 : 12
Now, Since the side is divided in the ratio of 8 : 12 , The area of ABD : ADC will also be divided in the ratio 8 : 12 by angle bisector theorem, let them be 8x and 12x. The total area will be 20x.
ABD : ABC = 8x : 20x = 8 : 20
Similarly ADC : ABC = 12 : 20
If this helps, please make it brainliest answer
Now, Since the side is divided in the ratio of 8 : 12 , The area of ABD : ADC will also be divided in the ratio 8 : 12 by angle bisector theorem, let them be 8x and 12x. The total area will be 20x.
ABD : ABC = 8x : 20x = 8 : 20
Similarly ADC : ABC = 12 : 20
If this helps, please make it brainliest answer
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