In ∆ABC , B is right angle, AB = 24 and AC = 25 . if angle A = a , angle C = b , find sin a , cos a, sin b , cos b and tan b
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Answer:
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In Δ ABC, B is at right angle.
Given, AB=24cm
BC=7cm
using Pythagoras theorem
AB2+BC2=AC2
⇒(24)2+(7)2=AC2
⇒AC=(242)+(7)2=576+49=625
⇒AC=25CM
(i)sin A=ACBC
=257
cos A=ACAB
=2524
(ii)sin C=ACAB
=2524
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Answered by
1
Step-by-step explanation:
BC=7
sin a = BC/AC=7/25
Cos a=AB/AC = 24/25
Sin b = AB/AC =24 /25
Cos b = BC/ AC= 7/25
Tan b = AB/BC = 24/7
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