Math, asked by arpit6768, 7 months ago

In ∆ABC , B is right angle, AB = 24 and AC = 25 . if angle A = a , angle C = b , find sin a , cos a, sin b , cos b and tan b​

Answers

Answered by anshuman1052
3

Answer:

Hy mate here is your answer

E.F image

In Δ ABC, B is at right angle.

Given, AB=24cm

BC=7cm

using Pythagoras theorem 

AB2+BC2=AC2

⇒(24)2+(7)2=AC2

⇒AC=(242)+(7)2=576+49=625

⇒AC=25CM

(i)sin A=ACBC

=257

cos A=ACAB

=2524

(ii)sin C=ACAB

=2524

If my answer is helpful to you please mark me as a brainiest

Answered by ektajamdhade
1

Step-by-step explanation:

BC=7

sin a = BC/AC=7/25

Cos a=AB/AC = 24/25

Sin b = AB/AC =24 /25

Cos b = BC/ AC= 7/25

Tan b = AB/BC = 24/7

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