In ΔABC, ∠BAC = (6x + 3)° and ∠ABC = (3x - 6)°. Which of these is ∠BCA? 1 180° - [(6x + 3)° - (3x - 6)°] 2 180° - [(6x + 3)° + (3x - 6)°] 3 180° + (6x + 3)° - (3x - 6)° 4 180° + (6x + 3)° + (3x - 6)°
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2. 180-(6x+3⁰)+(3x+6⁰)
bcoz ang 1 +ang 2+ang 3=180⁰ angle sum property
to find ang 3=180-ang1+ang2
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