In ΔABC,∠BAC = 90° and AD ⊥ BC. BD = 9cm , DC = 16cm Then find AD and AC
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Answer:
AD=12cm & AC=20cm
Step-by-step explanation:
In∆ABC,
AngleBAC=90°
segAD perpendicular to segBC
•°•AD²=BD×DC
•°•AD²=9×16
•°•AD²=144
•°•AD=√144
•°•AD=12cm
In∆ADC,
by pythagoras theorem
AC²=AD²+DC²
•°•AC²=144+256
•°•AC²=400
•°•AC=√400
•°•AC=20cm
Answr:AD=12cm & AC=20cm
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