In ∆ABC, BC =11 cm, CA=13 cm and the median to side AB is 10 cm. What is the area of ∆ABC
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AB=10CM
BC=11CM
AC=13CM
Step-by-step explanation:
Area of triangle ABC =1/2×base ×height
=1/2+BC×AC
=1/2×11×13
=71.5sq.cm
therefore area of triangle ABC is 71.5cm
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