In ∆ABC,BC=8,AB=16 and hight corresponding to BC is 10cm find
i)the area of∆ABC
ii)hight corresponding to AB
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I) 40 cm^2
ii) 5 cm
Step-by-step explanation:
Area = 1/2 x base x height
= 1/2 x 8 x 10
= 40 cm^2
let, h is height correspond to AB
1/2 x 16 x h = 40
8h = 40
h = 5 cm
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