Question

in ∆ABC,BC²=AB²+AC²and ∆B=50 then ∆C=​

Answer 1

Answer:

given BC²=AB²+AC2

<C=50

we know

<A+<B+<C=180

x+x+50=180

2x+50=180

2x=180-50

2x=130

x=130/2

x=65

AB=AC

<A=<C

therefore

<C=65

Answer 2

Answer:

given BC²=AB²+AC2

<C=50  

we know  

<A+<B+<C=180  

x+x+50=180  

2x+50=180  

2x=180-50  

2x=130  

x=130/2  

x=65  

AB=AC  

<A=<C  

therefore  

<C=65

Step-by-step explanation:

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