In ∆ABC, BE is the median and O is the midpoint of BE. Draw AO and extend it to meet BC at D. Draw CO and extend it to meet BA at F.
If CD=15, BD=5, AO=12, AF=9.
Then,
find,
(i)OD
(ii)BF
More helpful if provided an explanation also, thanks.
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Hey..!
I tried a lot but the given values suggest that OD=3, BF=3. However, O cannot be the midpoint of BE. My calculations show that, OB:OE=2:3 by using Menelaus’s Theorem to triangles ADC (with BOE as the transversal) & ABD ( with COF as the transversal).
Please verify this.
I tried a lot but the given values suggest that OD=3, BF=3. However, O cannot be the midpoint of BE. My calculations show that, OB:OE=2:3 by using Menelaus’s Theorem to triangles ADC (with BOE as the transversal) & ABD ( with COF as the transversal).
Please verify this.
AdiK1needy:
Thank you, thank you, THANK YOU A LOT, I was scratching my head for this question for a long time
Could you please also tell what is Menelaus Theorem?
oye i m here
bipasha
i m veer
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