Question

In ∆ABC C,=90°, AC =BC = 6cm ,find AB

Answer 1

$\textbf{Concept used:}$

$\textbf{Pythagors theorem:}$

$\text{In a right angled square on the hypotenuse is equal}$

$\text{to sum of the squares on the other two sides.}$

$\text{In right angled \traingle ABC,}\;\text{by Pythagoras theorem}$

$AB^2=AC^2+BC^2$

$AB^2=6^2+6^2$

$AB^2=36+36$

$AB^2=2{\times}36$

$\implies\boxed{\bf\;AB=6\sqrt{2}}$

Find more:

∆PQR is an isosceles triangle ,right angled at R . prove that PQ^2=2PR^2

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