Question

In ∆ABC, C = 90°, BC = 24 cm and AC = 7 cm. Find the values of sin A,cosec A and cot A.​

Answer 1

Ans is this for this question

Answer 2

SOL:- In ∆ ABC, C=90°

REASON-Pythagoras thm

Therefore

${ab }^{2} = bc {}^{2} + ac {}^{2}$

Therefore

${ab}^{2} = 24 {}^{2} + {7}^{2} = 625$

ab=25cm

sinA=opp/hyp

=BC/AC

=24/25

cosecA=1/sinA

=25/24

cotA=adj/opp

=AC/BC

=7/24