Question

In ∆ABC, ∠C = 90°, l(AC) = 8 cm and l(BC) = 15 cm. What is the length of seg (AB)?​

Answer 1

Answer:

c /ac and bc =15 ab ac-bc=180°

Answer 2

AnsWeR :

$\large\sf\implies AB = 17cm$

Solution :

Given :

• ∠C = 90° (Hence, right angled triangle)
• AC = 8 cm.
• BC = 15 cm.

To Find :

• Length of AB.

It is right angled triangle.So, we can find the length of AB using Pythagoras theorem,

$\red{\bigstar}\boxed{\sf H^2=B^2+P^2}$

Where,

• P is perpendicular.
• B is base.
• H is hypotenuse.

$\red{\bigstar}$AC is perpendicular.

$\red{\bigstar}$BC is Base.

$\red{\bigstar}$AB is hypotenuse.

[REFER TO THE ATTACHMENT PROVIDED]

So,

$\sf AB^2=AC^2+BC^2$

Putting the values ,

$\sf AB^2=8^2+15^2\\\\ \sf \implies AB^2=64+225 \\\\\sf\implies AB^2 = 289 \\\\\sf\implies AB = \sqrt{289} \\\\\implies\sf \boxed{\sf 17 \: cm}$

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