Question

in ∆Abc, ∆c =90°,tanA=1/√3 and tanB=1/√3 then show that sinAcosB+cosAsinB=1​

Answer 1

Answer:

here is your answer .....

Answer 2

Answer:

tan a = 1/root 3 given

Step-by-step explanation:

tan =1 /root3 = opp/adj

so sina=opp/hyp

hsquare=opp square+adj square

h square=1 square+root 3squsre

h square=1+3

h=2

sin1/4 cosroot3/4+cos root 3/4 sin1/4

=1