*In ∆ ABC,cos (B+C) is equal to _____*
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In ∆ ABC
ANGLE A + ANGLE B + ANGLE C = 180
ANGLE B + ANGLE C = 180 - Angle A
cos (B+C) = Sin (90-180 + Angle A)
= Sin ( Angle A - 90)
ANGLE A + ANGLE B + ANGLE C = 180
ANGLE B + ANGLE C = 180 - Angle A
cos (B+C) = Sin (90-180 + Angle A)
= Sin ( Angle A - 90)
AbhishekGhanwat:
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