In ∆ABC,D,E,are them midpoints of AB &AC Such that DE =4 .Find BC
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GMAT Club Forum Index Problem Solving (PS)
In triangle ABC, if BC = 3 and AC = 4, then what is the : Problem Solving (PS)
TAGS:
Difficulty: 700-Level Source: Manhattan GMAT
Topic Discussion
Page 1 of 2 1 2
enigma123
Feb 1, 2012
00:00
A
B
C
D
E
DIFFICULTY:
75% (hard)
QUESTION STATS:
based on 577 sessions
61% (01:41) correct
39% (01:25) wrong
Triangle.jpg (8.62 KiB) Viewed 209668 times
In triangle ABC, if BC = 3 and AC = 4, then what is the length of segment CD?
A. 3
B. 15/4
C. 5
D. 16/3
E. 20/3
[Reveal] Spoiler: OA
Last edited by Bunuel on 19 Dec 2012, 02:41, edited 2 times in total.
Reason: Edited the question and added the figure
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rvinodhini
Feb 26, 2012
Hi
I need a quick clarification on the concept of perpendicular bisector.
With a perpendicular bisector, the bisector always crosses the line segment at right angles
If any line cuts another line at 90 then it should be a perpendicular bisector right - i.e it divided the line segment into equal halves at 90 ?
So here BC should be the perpendicular bisector and the AC=CD=3 right ?
Please let me know what am missing here.
I do understand the explanations in the other thread mentioned,but can someone clarify as to why AC is not the perpendicular bisector ?
HOMENEW POSTSFORUMTESTSDEALS & DISCOUNTSREVIEWSCHAT GMAT Club Rules
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Close
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GMAT Club Forum Index Problem Solving (PS)
In triangle ABC, if BC = 3 and AC = 4, then what is the : Problem Solving (PS)
TAGS:
Difficulty: 700-Level Source: Manhattan GMAT
Topic Discussion
Page 1 of 2 1 2
enigma123
Feb 1, 2012
00:00
A
B
C
D
E
DIFFICULTY:
75% (hard)
QUESTION STATS:
based on 577 sessions
61% (01:41) correct
39% (01:25) wrong
Triangle.jpg (8.62 KiB) Viewed 209668 times
In triangle ABC, if BC = 3 and AC = 4, then what is the length of segment CD?
A. 3
B. 15/4
C. 5
D. 16/3
E. 20/3
[Reveal] Spoiler: OA
Last edited by Bunuel on 19 Dec 2012, 02:41, edited 2 times in total.
Reason: Edited the question and added the figure
Kudos
2
Bookmark 24
rvinodhini
Feb 26, 2012
Hi
I need a quick clarification on the concept of perpendicular bisector.
With a perpendicular bisector, the bisector always crosses the line segment at right angles
If any line cuts another line at 90 then it should be a perpendicular bisector right - i.e it divided the line segment into equal halves at 90 ?
So here BC should be the perpendicular bisector and the AC=CD=3 right ?
Please let me know what am missing here.
I do understand the explanations in the other thread mentioned,but can someone clarify as to why AC is not the perpendicular bisector ?
Answered by
1
If DE is 4 then , BC = 2 DE
BC = 2(4)
BC = 8..
BC = 2(4)
BC = 8..
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