Question

In ∆ ABC, D is a point on AB such that AD = 1/4 AB and E is a point on AC such that AE = 1/4 AC. Prove that DE = 1/4 BC​

Answer 1

Answer:

Step-by-step explanation:

By converse of basic proportionality theorem DE is parallel to BC

Now in ABC and ADE

Angle A is common

Angle D= Angle B corresponding angles.

Hence two triangles are similar.

Hence DE/BC=AD/AB=AE/AC=1/4

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