Question

in ∆ ABC, d is a point on side bc such d. if bd= 12cm.cd= 4cm then value of a (∆ACD) :A(∆ ABC) ​

Answer 1

Answer:

△ ABC and △ CAD

∠ABD=∠CAD (Given)

∠ACB=∠ACD (Common angle)

∠CAB=∠CDA (Third angle)

Hence, △ABC∼△DAC (AAA rule)

Ar.△BCAAr.△ACD=AB2AD2 (Ratio of areas of similar triangles is equal to ratio of square of corresponding sides)

Ar.△BCAAr.△ACD=5242

Ar.△BCAAr.△ACD=2516