Question

In ABC, D is the mid-point of BC. If
DL is perpendicular to AB and DM is perpendicular to AC such that DL = DM,
prove that AB=AC.​

Answer 1

Step-by-step explanation:

the answer is attached

Answer 2

Answer:

In TRIANGLE LBD and DMC and triangle

BD=DC (given)

angle BLD=Angle DMC(given and both are 90degree)

LD=MD(Given)

so by SAS concurrency rule triangle LBD is congurent to triangle DMC

and by CPCT angle B = angle C

we know that if base angles of a triangle are same then the sides opposite to the angles are also equal or it is isosceles triangle.

hope it helps you