In ∆ABC, D is the midpoint of base BC. DE and DF are perpendiculars to AB and AC respectively such that DE = DF. Prove that ÐB = ÐC.
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Given : DE and DF are perpendiculars to AB and AC.
To proof : DB = DC
To prove : In Δ ABC ,
Δ BED is congruent to Δ CFD
side DE is perpendicular to side AB
side DE is perpendicular to side AC
Therefore, side DB = side DC
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