In ∆ABC, D is the midpoint of BC and AB=AC. Prove that ∆ ABD ≅ ∆ ACD.
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In triangle ABD and ACD,
AD=AD
AB=AC
BC=CD [D is mid-point at BC]
(b) By using part a of the solution, we get
∴ △ABD≅△ACD ... SSS criterion
Step-by-step explanation:
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