In ABC, DE || AB. If AD = 6 cm, AB = 10 cm, AE = 9 cm, then
AC is equal to
(a)7.5 cm (b) 8 cm
(c)15 cm (d) 6 cm
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Given:
In ABC, DE || BC
AD = 6 cm
AB = 10 cm
AE = 9 cm
To find:
Value of AC
Solution:
By using the Intercept theorem that states that if a line is parallel (DE) to one side (BC) of a triangle it divides the other two sides (AB and AC) proportionally
Therefore, we can say that AD by AB is proportional to AE by AC.
AD/AB = AE/AC
Substituting the values,
6/10 = 9/AC
6/90 = 1/AC
AC = 90/6
AC = 15 cm
Therefore, the value of AC is equal to 15cm.
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