Question

In ∆ABC,DE,||BC,AD=4cm,DB=6cm and AE=5cm then the value EC=​

Answer 1

Answer:

EC=7.5cm

Step-by-step explanation:

In ΔABC,

DE||BC(Given)

$\frac{ad}{db} = \frac{ae}{ec} \: (bpt \: theorem)$

$\frac{4}{6} = \frac{5}{ec}$

$cross \: multiply$

$4ec = 6 \times 5$

$4ec = 30$

$ec = \frac{30}{4} = \frac{15}{2} = 7.5$

The value of EC is 7.5cm