In ∆abc de||Bc ad=x+1 db=x-1 ae=x+3 ec=x find x
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Answer:
x=3
Step-by-step explanation:
AD/DB=AE/EC
x+1/x-1=x+3/x
x(x+1)=(x-1)(x+3)
x²+x=x²+3x-x-3
x=2x-3
2x-x=3
x=3
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