Question

In ∆
ABC, DE || BC, AD = X + 2, DB = X-1, AE = x and EC = x - 2, then find x.
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Answer 1

the above is the formula application and next to it is calculation

i hope it helps... please mark as brainliest

Answer 2

Given, DE//BC

$\frac{AD}{DB} = \frac{AE}{EC} \\ \\ \frac{x}{x -2 } = \frac{x + 2}{x - 1} \\ \\ x(x - 1) = (x + 2)(x - 2) \\ \\ {x}^{2} + x = {x}^{2} + 4 \\ \\ x = 4$