Math, asked by nikkubhairam64621, 1 year ago

In ΔABC, DE || BC and AD/DB = 3/5, AC = 5.6. Find AE.

Answers

Answered by vijaya2002
2

DE || BC and AD/DB = 3/5

AD/DB=AE/EC

3/5=AE/AC-AE

3/5=AE/5.6-AE

5AE=16.8-3AE (by cross multiplication)

8AE=16.8

AE=16.8/8

AE=2.1

Answered by Anonymous
0

Answer is in the above attachment.

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