In ∆ABC, DE ǁ BC, the value of x will be A X x + 3 D E X + 1 x + 5 B C
(a) 1 (b) 2 (c) 3 (d) 4
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1
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this is the correct answer I think so if you have any questions or need to be the bearer of you can do to you and your
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3 this is the answer
3 this is the answer
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