Question

In ∆ ABC, DE || CA such that BD = 2x +7,
DC = x - 3, AB = 3x - 3, and BE = 2x + 1.
Find the value of 'x'?​

Answer 1

Answer:

This can be find by

Step-by-step explanation:

since, DE || CA

therefore, BD/BC = BE/BA

By putting the value

$\frac{2x + 7}{3x + 4} = \frac{2x + 1}{3x - 3}$

we get-

=>(2x+7)(3x-3)=(3x+4)(2x+1)

=>6x^2+21x-6x-21=6x^2+8x+3x+4

=>16x-21=11x+4

=>5x=25

=>x=5