Question

in ABC, DE parallel BC, AD =9cm, DB= 4.5 cm and AC =18cm then find AEandCE​

Answer 1

Answer:

The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that AD=9 cm, DB=4.5 cm and AC= 18cm.

Using the basic proportionality theorem, we have

AB/AA = AC/AA = BC/DE

⇒ AB/AA= AC/AE

⇒ 15/9= 18/AE

⇒9×18=15×AE

⇒162=AE

⇒162/15= AE

⇒10.8=AE

Hence, AE=10.8 cm.

solution