Question

In ∆ ABC,de parallel to BC,ad=x,db=x-2,ae=x+2and ec=x-1 find the value of x

Answer 1

$as \: per \: bpt \\ ad \div db = ae \div ec \\ x \div x - 2 = x + 2 \div x - 1 \\ x { }^{2} - x = x {}^{2} - 4 \\ x = 4$

Answer 2

Answer:

4

Step-by-step explanation: