Question

InΔABC ΔDEF, AB=DE,angleB=angleE and angleA=angleD. Prove that AC=DF

Answer 1

In ∆ABC and ∆DEF

AB=DE(GIVEN)

ANGLE B=ANGLE E (GIVEN)

ANGLE A=ANGLE D(GIVEN)

therefore ∆ABC is congruent to ∆DEF

and AC=DF(by cpct)

hope it helps you

Answer 2

Answer:

In ABC and DEF

AB=DE(given)

angle B=angleE(given)

angle A=angleD(given)

so, triangle ABC is congruent to triangle DEF(ASA)

therefore, AC=DF(By CPCT)

Hence proofed