Question

in ∆ABC~ ∆DEF, <A =70, <B=50, <F=60 and AB:DE=4:5, then are (∆ABC: ar(∆DEF)is.​

Answer 1

Answer:

In △ABC and △DEF

∠B=∠E (given)

∠C=∠F (Given)

∠A=∠D (third angle)

Thus, △ABC∼△DEF (AAA rule)

Given, AB=3DE Since, AB=DE

The two triangles are similar but not congruent.

Step-by-step explanation:

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