in ∆ABC~ ∆DEF, <A =70, <B=50, <F=60 and AB:DE=4:5, then are (∆ABC: ar(∆DEF)is.
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In △ABC and △DEF
∠B=∠E (given)
∠C=∠F (Given)
∠A=∠D (third angle)
Thus, △ABC∼△DEF (AAA rule)
Given, AB=3DE Since, AB=DE
The two triangles are similar but not congruent.
Step-by-step explanation:
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