Question

in ∆ABC ,E and F are mid points of AB and AC and join EF then EF||BCand EF=BC IF LENGHT OF BC IS 10 cm then what is lenght​

Answer 1

Answer:

$\huge{❥}\:{\mathtt{{\purple{\boxed{\tt{\pink{\red{A}\pink{n}\orange{s}\green{w}\blue{e}\purple{r᭄}}}}}}}}$

Given ABC is a triangle. E and F are the

mid point of side AB and AC respectively

ED = BC

EF + FD = BC

FE + FE = BC

2FE = BC

$ef = \frac{1}{2} bc$

Hence proved.

Answer 2

Hello

$\huge\color{blue}\boxed{\colorbox{cyan}{αηsωεя}}$

By midpoint theorem , EF||BC and EF =1/2BC

5 = 1/2 BC

BC = 5x2 = 10 cm

Hope it's help uh...!!!