Question

in ∆ABC,given AB=ACand angle E =90°.prove that ∆ABC is congruent of ∆ABC​

Answer 1

Answer:

In triangle ABC,

AB=AC thus, ∠ABC=∠ACB (I) (Opposite angles of equal sides of triangle are equal)

Now, in △s DBC and ECB,

BC=BC (Common)

∠DBC=∠ECB=90 (Given)

∠EBC=∠DCB (From I)

Hence, △DBC≅△ECB (ASA Congruency)

or DC=BE (equal sides of triangle of opposite angle are equal)

Also, Given AB=AC

DC−AC=BE−AB

AD=AE