In ABC given that A(7, -3), B(5, 3) and C(3, -1), find the equation of line passing through A which is parallel to BC.
Answers
Given : In ABC given that A(7, -3), B(5, 3) and C(3, -1),
To Find : the equation of line passing through A which is parallel to BC
Solution:
B(5, 3) and C(3, -1),
Slope of BC = ( -1 - 3) / ( 3 - 5)
= (-4 / -2)
= 2
Slope of parallel lines are equal
Hence slope of line passing through A which is parallel to BC is 2
Equation of line with slope 2 passing through A(7, -3)
y - (-3) = 2 ( x - 7)
y + 3 = 2x - 14
=> y = 2x - 17
y = 2x - 17 is the equation of line passing through A which is parallel to BC
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