Question

In ∆ABC, height AD=3 cm. Its area is 9 cm2

. Then, its base BC is​

Answer 1

area of triangle = half × base × hight so, 9 cm= 1/2 × base× 3 cm

now' 9×3/2 = base

so, 27/2 =base

so, base = 13.5 cm

Answer 2

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Step-by-step explanation:

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