Question

In ∆ABC, height AD=3 cm. Its area is 9 cm2

. Then, its base BC is



a) 6 cm b) 9 cm c) 12 cm d) 3 cm​

Answer 1

HEY THERE

HAPPY TO HELP YOU❤✨

WE KNOW THAT THE AREA OF THE TRIANGLE IS GIVEN BY

$\frac{1}{2} \times base \times height$

SO ACCORDING TO THE QUESTION GIVEN

$9 = \frac{1}{2} \times b \times 3 \\ b = \frac{18}{3 } \\ b = 6cm$

THEREFORE THE HEIGHT OF THE GIVEN TRIANGLE IS 6cm

HOPE IT HELPS✨