in ∆abc ,hypotenuse AC=12cm and A=60°, then find the length of remaining sides.
Answers
Answered by
5
AB = AC cos 60° = 12*1/2 = 6 cm
BC = AC sin 60° = 12*√3/2 = 6√3 cm
BC = AC sin 60° = 12*√3/2 = 6√3 cm
Answered by
0
Using trigonometry,
cos(theta)=b/H
cos60=b/12
b=12×cos60
b=12×1/2=6
by Pythagoras theorem,
a^2+b^2=c^2
So,36+b^2=144
b^2=4
b=2
cos(theta)=b/H
cos60=b/12
b=12×cos60
b=12×1/2=6
by Pythagoras theorem,
a^2+b^2=c^2
So,36+b^2=144
b^2=4
b=2
Similar questions