Question

In ∆ ABC, if 2∆A = 3∆B = 6∆C calculate ∆A, ∆B and ∆C.​

Answer 1

Step-by-step explanation:

2A = 3B = 6C = x°

Therefore A = (x/2), B = (x/3), C = (x/6)

We know, A + B + C = 180°

or, x/2 + x/3 + x/6 = 180°

or, 3x + 2x + x = 1080°

or, 6x = 1080°

or, x = 180°

So A = (180/2) = 90°

B = (180/3) = 60°

C = (180/6) = 30°