Math, asked by gauravgupta2530, 1 year ago

In ΔABC, if 2angle A= 3angle B= 6angle C, calculate angle A , angle B, angle C.

Answers

Answered by neeldhaygude
13

Answer:

∠A=90° ∠B=60°  ∠C=30°

Step-by-step explanation:

GIVEN-  2∠A= 3∠B = 6∠C

SOLUTION- ∠A+∠B+∠C = 180° (ANGLE SUM PROPERTY OF TRIANGLE)

2∠A = 3∠B THUS ∠B= 2∠A/3

AND 2∠A = 6∠C THUS ∠C=2∠A/6 = ∠A/3

THEREFORE (∠A)+(2∠A/3)+(∠A/3) = 180

=(3∠A+2∠A+∠A/3)=180

6∠A/3=180  THUS ∠A=90°

∠B=2∠A/3  = 2*90/3= 60°

∠C= 90/3= 30°

THUS

∠A=90° ∠B=60°  ∠C= 30°

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