In ΔABC, if 2angle A= 3angle B= 6angle C, calculate angle A , angle B, angle C.
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Answer:
∠A=90° ∠B=60° ∠C=30°
Step-by-step explanation:
GIVEN- 2∠A= 3∠B = 6∠C
SOLUTION- ∠A+∠B+∠C = 180° (ANGLE SUM PROPERTY OF TRIANGLE)
2∠A = 3∠B THUS ∠B= 2∠A/3
AND 2∠A = 6∠C THUS ∠C=2∠A/6 = ∠A/3
THEREFORE (∠A)+(2∠A/3)+(∠A/3) = 180
=(3∠A+2∠A+∠A/3)=180
6∠A/3=180 THUS ∠A=90°
∠B=2∠A/3 = 2*90/3= 60°
∠C= 90/3= 30°
THUS
∠A=90° ∠B=60° ∠C= 30°
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