In ∆ ABC, if 3∠A = 4∠ = 6∠, calculate the measures of ∠, ∠, ∠.
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Answer:
A+B+C =180
Let 3A =4B=6C=k
K/3+k/4+k/6=180
9k/12=180
K=240
A=80, B=60,C=40
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