In Δ ABC, if 3∠A = 4∠B = 6∠C calculate ∠A∠B∠C
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∠A = 80° ∠B = 60° ∠C = 40°
Step by step explaination:
Let 3∠A = 4∠B = 6∠C = x
∠A = x/3, ∠B = x/4, ∠C = x/6
∠A + ∠B + ∠C = 180°
x/3 + x/4 + x/6 = 180°
x = 240°
Therefore,
∠A = 80° ∠B = 60° ∠C = 40°
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