Question

In ABC,if 3 A = 4 B = 6 C,calculate the angle​

Answer 1

Answer:

The angle are $80^0 , 60^0$ and $40^0$

Step-by-step explanation:

Given,

                     $3 A = 4 B = 6 C\\ \\ 3 A = 4 B\\ \\ B=\frac{3}{4}A----(1)\\ \\ 3A=6C\\ \\ C=\frac{3}{6}A----(2)$

We know that,

                     $A+B+C=180^0\\ \\ A+\frac{3}{4}A+\frac{A}{2} =180^0\\ \\ \frac{4A+3A+2A}{4} =180^0\\ \\ \frac{9A}{4}=180^0\\ \\ 9A=720^0\\ \\ A=\frac{720^0}{9}=80^0$

                   $B=\frac{3}{4}A=\frac{3}{4}(80)=60^0\\ \\ C=\frac{A}{2} =\frac{80^0}{2}=40^0$