In ΔABC, if 3∠A=4∠B=6∠C. Find the value of ∠A, ∠B, ∠C in degree.
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Answer:
A=80 ; B = 60 and C = 40.
Step-by-step explanation:
3A=6C and 3A=4B
THUS, A/2=C .............{1}
and 3/4A=B..............{2}
we know, A+B+C=180......................(angles of a triangle)
from {1} and {2},
A+3/4A+A/2=180
THUS, 9/4A=180
9A=720
A=80
Put A=80 in {1} and {2}
thus, C=40
and B=60.
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