Math, asked by praneeth3374, 2 days ago

In ∆ABC, if 3∠A = 4∠B = 6∠C then A : B : C = ?

Answers

Answered by anushkakashyap2169
1

Answer:

16:21:31

A=32

B=42

C=62

A:B:C

32:42:62

16:27:37

Step-by-step explanation:

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Answered by BʀᴀɪɴʟʏAʙCᴅ
1

\huge{\textbf{\textsf{\pink{Answer\::}}}}

→ 3∠A = 4∠B = 6∠C

Let,

→ 3∠A = 4∠B = 6∠C = x

→ ∠A = \sf{\dfrac{x}{3}}

→ ∠B = \sf{\dfrac{x}{4}}

→ ∠C = \sf{\dfrac{x}{6}}

We know that,

∠A + ∠B + ∠C = 180°

\sf{\dfrac{x}{3}~+~\dfrac{x}{4}~+~\dfrac{x}{6}} = 180°

x = 240°

Therefore,

  • ∠A = 80°

  • ∠B = 60°

  • ∠C = 40°

Hence,

→ ∠A : ∠B : ∠C = 8 : 6 : 4

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