Question

In ∆ABC, if 3A=4B =6C, calculate A, B and C.​

Answer 1

Answer:

Step-by-step explanation:

Let angle A be equal to x,

Now,

3A = 4B

3/4x = B

At the same time,

3A = 6C

3/6A = C

1/2x = C

We know that, According to angle sum property, Sum of angles in a triangle is equal to 180°

So,

A + B + C = 180°

x + 3/4x + 1/2x = 180

x ( 1 + 3/4 + 1/2 ) = 180

x ( 4 + 3 + 2 / 4 ) = 180

x ( 9/4) = 180

x = 20 * 4

x = 80 .

Now, Angle A = 80°

B = 3/4 ( 80 ) = 60°

C = 1/2 ( 80 ) = 40°

Therefore the Angles of a triangle are 80° ,60°, 40° respectively