Question

In ∆ABC, if 6rR=ac, then the linejoining the incentre and centroid is parallel to the side??​

Answer 1

Answer:

ANSWER

In △OBL,cosA=

OB

OL

=

R

r

⇒RcosA=r

⇒RcosA=4Rsin

2

A

sin

2

B

sin

2

C

⇒cosA=4sin

2

A

sin

2

B

sin

2

C

⇒cosA=cosA+cosB+cosC−1

⇒0=cosB+cosC−1⇒cosB+cosC=1

Step-by-step explanation:

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