In ❑ ABC , if a = 10, b = 8, c = 6 then find the values of
i) cos C ii) sin A/2 iii) cos A/2 iv) tan A/2 v)A (ABC) vi) sin C vii) tan C
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Step-by-step explanation:
The value of cot15
∘
.cot20
∘
.cot70
∘
.cot75
∘
is
=(cot15
∘
.cot75
∘
)(cot20
∘
cot70
∘
)
Now cot75
∘
=tan15
∘
and cot70
∘
=tan20
∘
. cot(90−θ)=tanθ
Therefore, the given expression can be written as
(cot15
∘
tan15
∘
)(cot20
∘
tan20
∘
)
=1×1=1
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