Question

In ΔABC, if ⦟A =100ᵒ, AD bisects ⦟A and AD perpendicular to BC then ⦟B is​

Answer 1

In △ABC,∠BAD+∠ADB+∠DBA=180°

By angle sum property of a triangle

50°+90°+∠DBA=180°

⇒∠DBA=180°−140 ° =40°

∴∠B=40°

Answer 2

Answer:

angle B = 40

Step-by-step explanation:

in triangle ABD

angle BAD = 1/2 (100) (angle bisector)

angle ADC = 90 (perpendicular )

Angle ABD

A = 180- (90 +50)

= 40